What are the solutions to the equation x^2+8x-84=0 ?

The solutions to the equation x^2+8x-84=0 are x=6,x=-14

Find the zeros of x^2+8x-84=0

The zeros of x^2+8x-84=0 are x=6,x=-14

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x^{2} + 8 x - 84 = 0

x = 6, x = - 14

Solution steps

x^{2} + 8 x - 84 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 84 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 84) = 20

x_{1, 2} = \frac{- 8 \pm 20}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 20}{2 \cdot 1}, x_{2} = \frac{- 8 - 20}{2 \cdot 1}

x = \frac{- 8 + 20}{2 \cdot 1} : 6

x = \frac{- 8 - 20}{2 \cdot 1} : - 14

The solutions to the quadratic equation are:

x = 6, x = - 14

\frac{1}{27} y^{9} - \frac{27}{1000} x^{12}

x^{2} + 5 x \leq 6

(\frac{7}{4})^{- 2}

x^{4} + 5 x^{2} - 36

x^{2} - 4 x - 91 = 0

What are the solutions to the equation x^2+8x-84=0 ?
The solutions to the equation x^2+8x-84=0 are x=6,x=-14
Find the zeros of x^2+8x-84=0
The zeros of x^2+8x-84=0 are x=6,x=-14