What are the solutions to the equation 4x^2-28x=-11 ?

The solutions to the equation 4x^2-28x=-11 are x=(7+sqrt(38))/2 ,x=(7-sqrt(38))/2

Find the zeros of 4x^2-28x=-11

The zeros of 4x^2-28x=-11 are x=(7+sqrt(38))/2 ,x=(7-sqrt(38))/2

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4 x^{2} - 28 x = - 11

x = \frac{7 + 38}{2}, x = \frac{7 - 38}{2}

Decimal Notation

x = 6.58220 \dots, x = 0.41779 \dots

Solution steps

4 x^{2} - 28 x = - 11

Move

11

to the left side

4 x^{2} - 28 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 \cdot 4 \cdot 11}{2 \cdot 4}

(- 28)^{2} - 4 \cdot 4 \cdot 11 = 438

x_{1, 2} = \frac{- ( - 28 ) \pm 4 38}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 28 ) + 4 38}{2 \cdot 4}, x_{2} = \frac{- ( - 28 ) - 4 38}{2 \cdot 4}

x = \frac{- ( - 28 ) + 4 38}{2 \cdot 4} : \frac{7 + 38}{2}

x = \frac{- ( - 28 ) - 4 38}{2 \cdot 4} : \frac{7 - 38}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 38}{2}, x = \frac{7 - 38}{2}

- x + 6 > 17

(\frac{5}{2})^{10} \cdot ((\frac{5}{4})^{5})^{- 2}

3 x^{2} + 6 x - 6 = 0

w^{5} x^{5} y^{5} - w x^{4} y^{5}

2 x^{2} + 9 x + 10 = 0

What are the solutions to the equation 4x^2-28x=-11 ?
The solutions to the equation 4x^2-28x=-11 are x=(7+sqrt(38))/2 ,x=(7-sqrt(38))/2
Find the zeros of 4x^2-28x=-11
The zeros of 4x^2-28x=-11 are x=(7+sqrt(38))/2 ,x=(7-sqrt(38))/2