What are the solutions to the equation p^2=-3 ?

The solutions to the equation p^2=-3 are p=sqrt(3)i,p=-sqrt(3)i

Find the zeros of p^2=-3

The zeros of p^2=-3 are p=sqrt(3)i,p=-sqrt(3)i

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p^{2} = - 3

p = 3 i, p = - 3 i

Solution steps

p^{2} = - 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

p = - 3, p = - - 3

- 3 = 3 i

- - 3 = - 3 i

p = 3 i, p = - 3 i

x^{4} - 2 x^{3} - 8 x + 16

81 x^{6} - (y + 1)^{2}

\frac{5 ( x - 2 )}{6} - x = 1 - \frac{x}{9}

20 - 23 [(2 - 8) + (6 + 2) (2 - 7)] - 4 - 3 + 7 [2 - 5 (2 - 6)]

\frac{w}{2} - 1 \geq 1

What are the solutions to the equation p^2=-3 ?
The solutions to the equation p^2=-3 are p=sqrt(3)i,p=-sqrt(3)i
Find the zeros of p^2=-3
The zeros of p^2=-3 are p=sqrt(3)i,p=-sqrt(3)i