What are the solutions to the equation 3=x^2+5x ?

The solutions to the equation 3=x^2+5x are x=(-5+sqrt(37))/2 ,x=(-5-sqrt(37))/2

Find the zeros of 3=x^2+5x

The zeros of 3=x^2+5x are x=(-5+sqrt(37))/2 ,x=(-5-sqrt(37))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 = x^{2} + 5 x

x = \frac{- 5 + 37}{2}, x = \frac{- 5 - 37}{2}

Decimal Notation

x = 0.54138 \dots, x = - 5.54138 \dots

Solution steps

3 = x^{2} + 5 x

Switch sides

x^{2} + 5 x = 3

Move

3

to the left side

x^{2} + 5 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 3) = 37

x_{1, 2} = \frac{- 5 \pm 37}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 37}{2 \cdot 1}, x_{2} = \frac{- 5 - 37}{2 \cdot 1}

x = \frac{- 5 + 37}{2 \cdot 1} : \frac{- 5 + 37}{2}

x = \frac{- 5 - 37}{2 \cdot 1} : \frac{- 5 - 37}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 37}{2}, x = \frac{- 5 - 37}{2}

245 - 80 + 20

9 x^{2} - 7 x = 0

(8^{2})^{\frac{1}{3}}

\frac{c}{c - 2} - \frac{c ^{2}}{c ^{2} - 2 c}

x^{2} + 7 x - 8 = 0

What are the solutions to the equation 3=x^2+5x ?
The solutions to the equation 3=x^2+5x are x=(-5+sqrt(37))/2 ,x=(-5-sqrt(37))/2
Find the zeros of 3=x^2+5x
The zeros of 3=x^2+5x are x=(-5+sqrt(37))/2 ,x=(-5-sqrt(37))/2