What are the solutions to the equation 3x(x+2)=4 ?

The solutions to the equation 3x(x+2)=4 are x=(-3+sqrt(21))/3 ,x=-(3+sqrt(21))/3

Find the zeros of 3x(x+2)=4

The zeros of 3x(x+2)=4 are x=(-3+sqrt(21))/3 ,x=-(3+sqrt(21))/3

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3 x (x + 2) = 4

x = \frac{- 3 + 21}{3}, x = - \frac{3 + 21}{3}

Decimal Notation

x = 0.52752 \dots, x = - 2.52752 \dots

Solution steps

3 x (x + 2) = 4

Expand

3 x (x + 2) : 3 x^{2} + 6 x

3 x^{2} + 6 x = 4

Move

4

to the left side

3 x^{2} + 6 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

6^{2} - 4 \cdot 3 (- 4) = 221

x_{1, 2} = \frac{- 6 \pm 2 21}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 6 + 2 21}{2 \cdot 3}, x_{2} = \frac{- 6 - 2 21}{2 \cdot 3}

x = \frac{- 6 + 2 21}{2 \cdot 3} : \frac{- 3 + 21}{3}

x = \frac{- 6 - 2 21}{2 \cdot 3} : - \frac{3 + 21}{3}

The solutions to the quadratic equation are:

x = \frac{- 3 + 21}{3}, x = - \frac{3 + 21}{3}

3 x^{2} + 16 = 2

4 x^{4} y + 10 x^{3} y - 36 x^{2} y - 90 x y

x^{2} - 5 x = 2

10 - 10 ∣ - 8 k + 4 ∣ = 10

\frac{10 ( x + y ) ^{3}}{4 ( x + y ) ^{- 2}}

What are the solutions to the equation 3x(x+2)=4 ?
The solutions to the equation 3x(x+2)=4 are x=(-3+sqrt(21))/3 ,x=-(3+sqrt(21))/3
Find the zeros of 3x(x+2)=4
The zeros of 3x(x+2)=4 are x=(-3+sqrt(21))/3 ,x=-(3+sqrt(21))/3