What are the solutions to the equation w(2w-3)=27 ?

The solutions to the equation w(2w-3)=27 are w= 9/2 ,w=-3

Find the zeros of w(2w-3)=27

The zeros of w(2w-3)=27 are w= 9/2 ,w=-3

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w (2 w - 3) = 27

w = \frac{9}{2}, w = - 3

Decimal Notation

w = 4.5, w = - 3

Solution steps

w (2 w - 3) = 27

Expand

w (2 w - 3) : 2 w^{2} - 3 w

2 w^{2} - 3 w = 27

Move

27

to the left side

2 w^{2} - 3 w - 27 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 27 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 27) = 15

w_{1, 2} = \frac{- ( - 3 ) \pm 15}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- ( - 3 ) + 15}{2 \cdot 2}, w_{2} = \frac{- ( - 3 ) - 15}{2 \cdot 2}

w = \frac{- ( - 3 ) + 15}{2 \cdot 2} : \frac{9}{2}

w = \frac{- ( - 3 ) - 15}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

w = \frac{9}{2}, w = - 3

∣ (3 x + 4) - 4 ∣ < 0.01

\frac{51 - x}{60} + 0.95 = \frac{x}{31}

2 z^{2} + z + 2 = 0

x^{2} - 6 x + 7 = 2

7 p^{2} + 8 p - 1 = 5 p^{2}

What are the solutions to the equation w(2w-3)=27 ?
The solutions to the equation w(2w-3)=27 are w= 9/2 ,w=-3
Find the zeros of w(2w-3)=27
The zeros of w(2w-3)=27 are w= 9/2 ,w=-3