What are the solutions to the equation -5y^2+8y+8=8y+3 ?

The solutions to the equation -5y^2+8y+8=8y+3 are y=1,y=-1

Find the zeros of -5y^2+8y+8=8y+3

The zeros of -5y^2+8y+8=8y+3 are y=1,y=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 5 y^{2} + 8 y + 8 = 8 y + 3

y = 1, y = - 1

Solution steps

- 5 y^{2} + 8 y + 8 = 8 y + 3

Move

8

to the right side

- 5 y^{2} + 8 y = 8 y - 5

Move

8 y

to the left side

- 5 y^{2} = - 5

Divide both sides by

- 5

y^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 1, y = - 1

1 = 1

- 1 = - 1

y = 1, y = - 1

x^{2} - 12 x + 45 = 0

16 x^{2} - 121 y^{2}

(\frac{3}{2} + \frac{1}{2} i)^{3}

\frac{2}{1}

(n + 7)^{2} = - 2 n

What are the solutions to the equation -5y^2+8y+8=8y+3 ?
The solutions to the equation -5y^2+8y+8=8y+3 are y=1,y=-1
Find the zeros of -5y^2+8y+8=8y+3
The zeros of -5y^2+8y+8=8y+3 are y=1,y=-1