What are the solutions to the equation x^2-8x+27=0 ?

The solutions to the equation x^2-8x+27=0 are x=4+sqrt(11)i,x=4-sqrt(11)i

Find the zeros of x^2-8x+27=0

The zeros of x^2-8x+27=0 are x=4+sqrt(11)i,x=4-sqrt(11)i

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x^{2} - 8 x + 27 = 0

x = 4 + 11 i, x = 4 - 11 i

Solution steps

x^{2} - 8 x + 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 27}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot 27 : 211 i

x_{1, 2} = \frac{- ( - 8 ) \pm 2 11 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 11 i}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 11 i}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 11 i}{2 \cdot 1} : 4 + 11 i

x = \frac{- ( - 8 ) - 2 11 i}{2 \cdot 1} : 4 - 11 i

The solutions to the quadratic equation are:

x = 4 + 11 i, x = 4 - 11 i

x^{3} + 3 x^{2} + 6 x + 18

- \frac{2}{3} + 1

4^{3} \cdot 4^{5}

ln (8) - ln (2)

12 = 2 x^{2} + 2 x - 12

What are the solutions to the equation x^2-8x+27=0 ?
The solutions to the equation x^2-8x+27=0 are x=4+sqrt(11)i,x=4-sqrt(11)i
Find the zeros of x^2-8x+27=0
The zeros of x^2-8x+27=0 are x=4+sqrt(11)i,x=4-sqrt(11)i