What are the solutions to the equation 7x^2+10x-4=0 ?

The solutions to the equation 7x^2+10x-4=0 are x=(-5+sqrt(53))/7 ,x=-(5+sqrt(53))/7

Find the zeros of 7x^2+10x-4=0

The zeros of 7x^2+10x-4=0 are x=(-5+sqrt(53))/7 ,x=-(5+sqrt(53))/7

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7 x^{2} + 10 x - 4 = 0

x = \frac{- 5 + 53}{7}, x = - \frac{5 + 53}{7}

Decimal Notation

x = 0.32572 \dots, x = - 1.75430 \dots

Solution steps

7 x^{2} + 10 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 7 ( - 4 )}{2 \cdot 7}

1 0^{2} - 4 \cdot 7 (- 4) = 253

x_{1, 2} = \frac{- 10 \pm 2 53}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 10 + 2 53}{2 \cdot 7}, x_{2} = \frac{- 10 - 2 53}{2 \cdot 7}

x = \frac{- 10 + 2 53}{2 \cdot 7} : \frac{- 5 + 53}{7}

x = \frac{- 10 - 2 53}{2 \cdot 7} : - \frac{5 + 53}{7}

The solutions to the quadratic equation are:

x = \frac{- 5 + 53}{7}, x = - \frac{5 + 53}{7}

2 x^{2} - 21 x + 40

x^{2} - 7 x = x - 14

\frac{4}{16}

(\frac{x}{7})^{2}

15 x^{2} - 2 x - 1 = 0

What are the solutions to the equation 7x^2+10x-4=0 ?
The solutions to the equation 7x^2+10x-4=0 are x=(-5+sqrt(53))/7 ,x=-(5+sqrt(53))/7
Find the zeros of 7x^2+10x-4=0
The zeros of 7x^2+10x-4=0 are x=(-5+sqrt(53))/7 ,x=-(5+sqrt(53))/7