What are the solutions to the equation 5^2+1^2=c^2 ?

The solutions to the equation 5^2+1^2=c^2 are c=sqrt(26),c=-sqrt(26)

Find the zeros of 5^2+1^2=c^2

The zeros of 5^2+1^2=c^2 are c=sqrt(26),c=-sqrt(26)

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5^{2} + 1^{2} = c^{2}

c = 26, c = - 26

Decimal Notation

c = 5.09901 \dots, c = - 5.09901 \dots

Solution steps

5^{2} + 1^{2} = c^{2}

Switch sides

c^{2} = 5^{2} + 1^{2}

Simplify

5^{2} + 1^{2} : 26

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 26, c = - 26

b^{2} - 64

3 x^{2} - 2 + 7 x = 0

\frac{x}{3} \leq - 4

\frac{( ( x + 2 ) )}{4} - \frac{( x - 2 )}{3} x = x + \frac{( 2 ( x - 3 ) )}{3} x

\frac{3}{7} - \frac{1}{6}

What are the solutions to the equation 5^2+1^2=c^2 ?
The solutions to the equation 5^2+1^2=c^2 are c=sqrt(26),c=-sqrt(26)
Find the zeros of 5^2+1^2=c^2
The zeros of 5^2+1^2=c^2 are c=sqrt(26),c=-sqrt(26)