What is ((4qh^{-3})^{-2})/(12q^8h^8) ?

The solution to ((4qh^{-3})^{-2})/(12q^8h^8) is 1/(192q^{10)h^2}

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simplify ((4qh^{-3})^{-2})/(12q^8h^8)

simplify

\frac{( 4 q h ^{- 3} ) ^{- 2}}{12 q ^{8} h ^{8}}

\frac{1}{192 q ^{10} h ^{2}}

Solution steps

\frac{( 4 q h ^{- 3} ) ^{- 2}}{12 q ^{8} h ^{8}}

Simplify

(4 q h^{- 3})^{- 2} : 4^{- 2} q^{- 2} h^{6}

= \frac{4 ^{- 2} q ^{- 2} h ^{6}}{12 q ^{8} h ^{8}}

Factor the number:

12 = 4 \cdot 3

= \frac{4 ^{- 2} q ^{- 2} h ^{6}}{4 \cdot 3 q ^{8} h ^{8}}

\frac{4 ^{- 2}}{4} = \frac{1}{4 ^{3}}

= \frac{q ^{- 2} h ^{6}}{4 ^{3} \cdot 3 q ^{8} h ^{8}}

Simplify

\frac{q ^{- 2}}{q ^{8}} : \frac{1}{q ^{10}}

= \frac{h ^{6}}{4 ^{3} \cdot 3 q ^{10} h ^{8}}

Simplify

\frac{h ^{6}}{h ^{8}} : \frac{1}{h ^{2}}

= \frac{1}{4 ^{3} \cdot 3 q ^{10} h ^{2}}

Simplify

4^{3} \cdot 3 q^{10} h^{2} : 192 q^{10} h^{2}

= \frac{1}{192 q ^{10} h ^{2}}

- 6 (3 z + 3) < - 2 (5 z - 4)

q^{2} + 18 q + 81 = 0

(x + 4) (x - 5) > 0

\frac{y ^{5}}{x ^{- 2} x ^{- 3} y ^{- 8}}

x^{4} - 3 x^{3} + 2 x^{2}

What is ((4qh^{-3})^{-2})/(12q^8h^8) ?
The solution to ((4qh^{-3})^{-2})/(12q^8h^8) is 1/(192q^{10)h^2}