What are the solutions to the equation 6x^2-17x-28=0 ?

The solutions to the equation 6x^2-17x-28=0 are x=4,x=-7/6

Find the zeros of 6x^2-17x-28=0

The zeros of 6x^2-17x-28=0 are x=4,x=-7/6

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6 x^{2} - 17 x - 28 = 0

x = 4, x = - \frac{7}{6}

Decimal Notation

x = 4, x = - 1.16666 \dots

Solution steps

6 x^{2} - 17 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 6 ( - 28 )}{2 \cdot 6}

(- 17)^{2} - 4 \cdot 6 (- 28) = 31

x_{1, 2} = \frac{- ( - 17 ) \pm 31}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 31}{2 \cdot 6}, x_{2} = \frac{- ( - 17 ) - 31}{2 \cdot 6}

x = \frac{- ( - 17 ) + 31}{2 \cdot 6} : 4

x = \frac{- ( - 17 ) - 31}{2 \cdot 6} : - \frac{7}{6}

The solutions to the quadratic equation are:

x = 4, x = - \frac{7}{6}

x^{3} + 7 \geq 0

(4 y + 8)^{2} = 64

x^{2} + 7 x + 12 = 0

\frac{2}{3} (6 - 9 x) = 16

8 x^{3} - 64 x^{2} + x - 8

What are the solutions to the equation 6x^2-17x-28=0 ?
The solutions to the equation 6x^2-17x-28=0 are x=4,x=-7/6
Find the zeros of 6x^2-17x-28=0
The zeros of 6x^2-17x-28=0 are x=4,x=-7/6