What are the solutions to the equation 3x^2+x-5=x+5 ?

The solutions to the equation 3x^2+x-5=x+5 are x=sqrt(10/3),x=-sqrt(10/3)

Find the zeros of 3x^2+x-5=x+5

The zeros of 3x^2+x-5=x+5 are x=sqrt(10/3),x=-sqrt(10/3)

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3 x^{2} + x - 5 = x + 5

x = \frac{10}{3}, x = - \frac{10}{3}

Decimal Notation

x = 1.82574 \dots, x = - 1.82574 \dots

Solution steps

3 x^{2} + x - 5 = x + 5

Move

5

to the right side

3 x^{2} + x = x + 10

Move

x

to the left side

3 x^{2} = 10

Divide both sides by

3

x^{2} = \frac{10}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{10}{3}, x = - \frac{10}{3}

\frac{1}{5} (1 - x) = \frac{1}{2}

20 x^{2} - 3 x - 9 = 0

- 4 x^{2} + 52 x = 144

458 (\frac{1}{2})^{\frac{50}{30}}

\frac{480}{5}

What are the solutions to the equation 3x^2+x-5=x+5 ?
The solutions to the equation 3x^2+x-5=x+5 are x=sqrt(10/3),x=-sqrt(10/3)
Find the zeros of 3x^2+x-5=x+5
The zeros of 3x^2+x-5=x+5 are x=sqrt(10/3),x=-sqrt(10/3)