What are the solutions to the equation -4x^2+52x=144 ?

The solutions to the equation -4x^2+52x=144 are x=4,x=9

Find the zeros of -4x^2+52x=144

The zeros of -4x^2+52x=144 are x=4,x=9

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- 4 x^{2} + 52 x = 144

x = 4, x = 9

Solution steps

- 4 x^{2} + 52 x = 144

Move

144

to the left side

- 4 x^{2} + 52 x - 144 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 52 \pm 5 2 ^{2} - 4 ( - 4 ) ( - 144 )}{2 ( - 4 )}

5 2^{2} - 4 (- 4) (- 144) = 20

x_{1, 2} = \frac{- 52 \pm 20}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 52 + 20}{2 ( - 4 )}, x_{2} = \frac{- 52 - 20}{2 ( - 4 )}

x = \frac{- 52 + 20}{2 ( - 4 )} : 4

x = \frac{- 52 - 20}{2 ( - 4 )} : 9

The solutions to the quadratic equation are:

x = 4, x = 9

458 (\frac{1}{2})^{\frac{50}{30}}

\frac{480}{5}

25 x^{2} + 20 x + 3

9^{2} + b^{2} = 4 1^{2}

2 lo g_{3} (\frac{1}{52})

What are the solutions to the equation -4x^2+52x=144 ?
The solutions to the equation -4x^2+52x=144 are x=4,x=9
Find the zeros of -4x^2+52x=144
The zeros of -4x^2+52x=144 are x=4,x=9