What are the solutions to the equation 12x^2+60x+75=0 ?

The solutions to the equation 12x^2+60x+75=0 are x=-5/2

Find the zeros of 12x^2+60x+75=0

The zeros of 12x^2+60x+75=0 are x=-5/2

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12 x^{2} + 60 x + 75 = 0

x = - \frac{5}{2}

Decimal

x = - 2.5

Solution steps

12 x^{2} + 60 x + 75 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 60 \pm 6 0 ^{2} - 4 \cdot 12 \cdot 75}{2 \cdot 12}

6 0^{2} - 4 \cdot 12 \cdot 75 = 0

x_{1, 2} = \frac{- 60 \pm 0}{2 \cdot 12}

x = \frac{- 60}{2 \cdot 12}

\frac{- 60}{2 \cdot 12} = - \frac{5}{2}

x = - \frac{5}{2}

The solution to the quadratic equation is:

x = - \frac{5}{2}

\frac{5 a}{a + 2} - \frac{3 a - 4}{a + 2}

2 x^{2} - 9 x

p^{6} + 1

x^{2} - 3 x = (x + 4) (x - 5)

7 x + 40 = 3 x + 112

What are the solutions to the equation 12x^2+60x+75=0 ?
The solutions to the equation 12x^2+60x+75=0 are x=-5/2
Find the zeros of 12x^2+60x+75=0
The zeros of 12x^2+60x+75=0 are x=-5/2