What are the solutions to the equation ((s+2)(s-3))=0 ?

The solutions to the equation ((s+2)(s-3))=0 are s=-2,s=3

Find the zeros of ((s+2)(s-3))=0

The zeros of ((s+2)(s-3))=0 are s=-2,s=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((s + 2) (s - 3)) = 0

s = - 2, s = 3

Solution steps

((s + 2) (s - 3)) = 0

Factor

((s + 2) (s - 3)) : (s + 2) (s - 3)

(s + 2) (s - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

s + 2 = 0 or s - 3 = 0

Solve

s + 2 = 0 : s = - 2

Solve

s - 3 = 0 : s = 3

The solutions to the quadratic equation are:

s = - 2, s = 3

18 x^{2} + 33 x - 30

x^{2} + 16 x + 6 = 0

1000 (\frac{9}{10})^{n} < 0.01

x^{5} + 5 x^{2} - 4 x^{3} - 20

2 (0) + y = 4

What are the solutions to the equation ((s+2)(s-3))=0 ?
The solutions to the equation ((s+2)(s-3))=0 are s=-2,s=3
Find the zeros of ((s+2)(s-3))=0
The zeros of ((s+2)(s-3))=0 are s=-2,s=3