What are the solutions to the equation 4x^2-20x=0 ?

The solutions to the equation 4x^2-20x=0 are x=5,x=0

Find the zeros of 4x^2-20x=0

The zeros of 4x^2-20x=0 are x=5,x=0

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4 x^{2} - 20 x = 0

x = 5, x = 0

Solution steps

4 x^{2} - 20 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 20)^{2} - 4 \cdot 4 \cdot 0 = 20

x_{1, 2} = \frac{- ( - 20 ) \pm 20}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 20}{2 \cdot 4}, x_{2} = \frac{- ( - 20 ) - 20}{2 \cdot 4}

x = \frac{- ( - 20 ) + 20}{2 \cdot 4} : 5

x = \frac{- ( - 20 ) - 20}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

x = 5, x = 0

\frac{1}{6} - \frac{1}{3}

100 x^{2} - 121 y^{2}

(3 x + 6)^{2} + 4 (3 x + 6) + 4 = 0

r = (- 3)^{2} + (- 2)^{2}

∣ 4 x - 23 ∣ = - 17

What are the solutions to the equation 4x^2-20x=0 ?
The solutions to the equation 4x^2-20x=0 are x=5,x=0
Find the zeros of 4x^2-20x=0
The zeros of 4x^2-20x=0 are x=5,x=0