What are the solutions to the equation x+10^2-x^2=50 ?

The solutions to the equation x+10^2-x^2=50 are x=-(-1+sqrt(201))/2 ,x=(1+sqrt(201))/2

Find the zeros of x+10^2-x^2=50

The zeros of x+10^2-x^2=50 are x=-(-1+sqrt(201))/2 ,x=(1+sqrt(201))/2

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x + 1 0^{2} - x^{2} = 50

x = - \frac{- 1 + 201}{2}, x = \frac{1 + 201}{2}

Decimal Notation

x = - 6.58872 \dots, x = 7.58872 \dots

Solution steps

x + 1 0^{2} - x^{2} = 50

Expand

x + 1 0^{2} - x^{2} : x + 100 - x^{2}

x + 100 - x^{2} = 50

Move

50

to the left side

- x^{2} + x + 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) \cdot 50}{2 ( - 1 )}

1^{2} - 4 (- 1) \cdot 50 = 201

x_{1, 2} = \frac{- 1 \pm 201}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 1 + 201}{2 ( - 1 )}, x_{2} = \frac{- 1 - 201}{2 ( - 1 )}

x = \frac{- 1 + 201}{2 ( - 1 )} : - \frac{- 1 + 201}{2}

x = \frac{- 1 - 201}{2 ( - 1 )} : \frac{1 + 201}{2}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 201}{2}, x = \frac{1 + 201}{2}

7 x^{2} + 3 x \geq 5 x^{2} + 2

x = \frac{x ^{2}}{2}

x + x + x = - 63

w^{2} + w - 30 = 0

What are the solutions to the equation x+10^2-x^2=50 ?
The solutions to the equation x+10^2-x^2=50 are x=-(-1+sqrt(201))/2 ,x=(1+sqrt(201))/2
Find the zeros of x+10^2-x^2=50
The zeros of x+10^2-x^2=50 are x=-(-1+sqrt(201))/2 ,x=(1+sqrt(201))/2