What is 2/3 g-1/2 (g-14)<= 1/6 (g+42) ?

The solution to 2/3 g-1/2 (g-14)<= 1/6 (g+42) is True for all g

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2/3 g-1/2 (g-14)<= 1/6 (g+42)

\frac{2}{3} g - \frac{1}{2} (g - 14) \leq \frac{1}{6} (g + 42)

True for all g

Interval Notation

(- \infty, \infty)

Solution steps

\frac{2}{3} g - \frac{1}{2} (g - 14) \leq \frac{1}{6} (g + 42)

Expand

\frac{2}{3} g - \frac{1}{2} (g - 14) : \frac{g}{6} + 7

Expand

\frac{1}{6} (g + 42) : \frac{1}{6} g + 7

\frac{g}{6} + 7 \leq \frac{1}{6} g + 7

Move

7

to the right side

\frac{g}{6} \leq \frac{1}{6} g

Multiply both sides by

6

\frac{g}{6} \cdot 6 \leq \frac{1}{6} g \cdot 6

Simplify

g \leq g

Move

g

to the left side

0 \leq 0

Therefore, the solution is

True for all g

s^{2} + 4 s + 3

r^{2} + 14 = 0

ln (9.25) = 2.2246

2 (x^{2} + 1) + 1 = 9

\frac{b ^{10}}{b ^{6}}

What is 2/3 g-1/2 (g-14)<= 1/6 (g+42) ?
The solution to 2/3 g-1/2 (g-14)<= 1/6 (g+42) is True for all g