What are the solutions to the equation 9^2+x^2=41^2 ?

The solutions to the equation 9^2+x^2=41^2 are x=40,x=-40

Find the zeros of 9^2+x^2=41^2

The zeros of 9^2+x^2=41^2 are x=40,x=-40

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9^{2} + x^{2} = 4 1^{2}

x = 40, x = - 40

Solution steps

9^{2} + x^{2} = 4 1^{2}

Move

9^{2}

to the right side

x^{2} = 1600

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1600, x = - 1600

1600 = 40

- 1600 = - 40

x = 40, x = - 40

3 (x - 4) = 15

4 v - 13 = 2 v - 5

5 x^{2} - 10 x + 2 = 0

\frac{( - a ^{4} b ^{5} ) ^{4}}{( a ^{8} b ^{10} ) ^{2}}

- 6 = \frac{n}{- 14} - 5

What are the solutions to the equation 9^2+x^2=41^2 ?
The solutions to the equation 9^2+x^2=41^2 are x=40,x=-40
Find the zeros of 9^2+x^2=41^2
The zeros of 9^2+x^2=41^2 are x=40,x=-40