What is ((-a^4b^5)^4)/((a^8b^{10))^2} ?

The solution to ((-a^4b^5)^4)/((a^8b^{10))^2} is 1

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simplify ((-a^4b^5)^4)/((a^8b^{10))^2}

simplify

\frac{( - a ^{4} b ^{5} ) ^{4}}{( a ^{8} b ^{10} ) ^{2}}

1

Solution steps

\frac{( - a ^{4} b ^{5} ) ^{4}}{( a ^{8} b ^{10} ) ^{2}}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- a^{4} b^{5})^{4} = (a^{4} b^{5})^{4}

= \frac{( a ^{4} b ^{5} ) ^{4}}{( a ^{8} b ^{10} ) ^{2}}

Simplify

(a^{4} b^{5})^{4} : a^{16} b^{20}

= \frac{a ^{16} b ^{20}}{( a ^{8} b ^{10} ) ^{2}}

Simplify

(a^{8} b^{10})^{2} : a^{16} b^{20}

= \frac{a ^{16} b ^{20}}{a ^{16} b ^{20}}

Cancel the common factor:

a^{16}

= \frac{b ^{20}}{b ^{20}}

Apply the fraction rule:

\frac{a}{a} = 1

= 1

- 6 = \frac{n}{- 14} - 5

\frac{1}{2} x^{2} - 8 = 16

x^{2} + 6 x + 4 = - 2 x + 4

- 19 < 3 x + 5 \leq 20

5 x^{2} = 55

What is ((-a^4b^5)^4)/((a^8b^{10))^2} ?
The solution to ((-a^4b^5)^4)/((a^8b^{10))^2} is 1