What are the solutions to the equation x^2+6x=8x+35 ?

The solutions to the equation x^2+6x=8x+35 are x=7,x=-5

Find the zeros of x^2+6x=8x+35

The zeros of x^2+6x=8x+35 are x=7,x=-5

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x^{2} + 6 x = 8 x + 35

x = 7, x = - 5

Solution steps

x^{2} + 6 x = 8 x + 35

Move

35

to the left side

x^{2} + 6 x - 35 = 8 x

Move

8 x

to the left side

x^{2} - 2 x - 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 35 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 35) = 12

x_{1, 2} = \frac{- ( - 2 ) \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 12}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 12}{2 \cdot 1}

x = \frac{- ( - 2 ) + 12}{2 \cdot 1} : 7

x = \frac{- ( - 2 ) - 12}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 7, x = - 5

(4)^{5}

x^{\frac{2}{5}} \cdot x^{\frac{1}{10}}

x^{2} + 12 x - 6 = 0

3 b^{3} - b^{3} + 2 b

\frac{9 - 8 i}{9 + i}

What are the solutions to the equation x^2+6x=8x+35 ?
The solutions to the equation x^2+6x=8x+35 are x=7,x=-5
Find the zeros of x^2+6x=8x+35
The zeros of x^2+6x=8x+35 are x=7,x=-5