What are the solutions to the equation r^2-1r-20=0 ?

The solutions to the equation r^2-1r-20=0 are r=5,r=-4

Find the zeros of r^2-1r-20=0

The zeros of r^2-1r-20=0 are r=5,r=-4

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r^{2} - 1 r - 20 = 0

r = 5, r = - 4

Solution steps

r^{2} - 1 \cdot r - 20 = 0

Refine

r^{2} - r - 20 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 20) = 9

r_{1, 2} = \frac{- ( - 1 ) \pm 9}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 1 ) + 9}{2 \cdot 1}, r_{2} = \frac{- ( - 1 ) - 9}{2 \cdot 1}

r = \frac{- ( - 1 ) + 9}{2 \cdot 1} : 5

r = \frac{- ( - 1 ) - 9}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

r = 5, r = - 4

- 2 (8)^{\frac{2}{3}} - 4

- x^{2} + 23 x - 132 = 0

2 π

\frac{7 π}{6} \cdot \frac{180}{π}

What are the solutions to the equation r^2-1r-20=0 ?
The solutions to the equation r^2-1r-20=0 are r=5,r=-4
Find the zeros of r^2-1r-20=0
The zeros of r^2-1r-20=0 are r=5,r=-4