What are the solutions to the equation -x^2-x+3=0 ?

The solutions to the equation -x^2-x+3=0 are x=-(1+sqrt(13))/2 ,x=(sqrt(13)-1)/2

Find the zeros of -x^2-x+3=0

The zeros of -x^2-x+3=0 are x=-(1+sqrt(13))/2 ,x=(sqrt(13)-1)/2

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- x^{2} - x + 3 = 0

x = - \frac{1 + 13}{2}, x = \frac{13 - 1}{2}

Decimal Notation

x = - 2.30277 \dots, x = 1.30277 \dots

Solution steps

- x^{2} - x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 1 ) \cdot 3}{2 ( - 1 )}

(- 1)^{2} - 4 (- 1) \cdot 3 = 13

x_{1, 2} = \frac{- ( - 1 ) \pm 13}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 13}{2 ( - 1 )}, x_{2} = \frac{- ( - 1 ) - 13}{2 ( - 1 )}

x = \frac{- ( - 1 ) + 13}{2 ( - 1 )} : - \frac{1 + 13}{2}

x = \frac{- ( - 1 ) - 13}{2 ( - 1 )} : \frac{13 - 1}{2}

The solutions to the quadratic equation are:

x = - \frac{1 + 13}{2}, x = \frac{13 - 1}{2}

1 1^{2} + 2^{2} = c^{2}

\frac{5}{2 + 3}

16 x^{2} = 49

x^{2} - x + 0 = 0

4 x^{2} - 31 x + 21

What are the solutions to the equation -x^2-x+3=0 ?
The solutions to the equation -x^2-x+3=0 are x=-(1+sqrt(13))/2 ,x=(sqrt(13)-1)/2
Find the zeros of -x^2-x+3=0
The zeros of -x^2-x+3=0 are x=-(1+sqrt(13))/2 ,x=(sqrt(13)-1)/2