What are the solutions to the equation x=(x-6)^2 ?

The solutions to the equation x=(x-6)^2 are x=9,x=4

Find the zeros of x=(x-6)^2

The zeros of x=(x-6)^2 are x=9,x=4

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x = (x - 6)^{2}

x = 9, x = 4

Solution steps

x = (x - 6)^{2}

Expand

(x - 6)^{2} : x^{2} - 12 x + 36

x = x^{2} - 12 x + 36

Switch sides

x^{2} - 12 x + 36 = x

Move

x

to the left side

x^{2} - 13 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot 36 = 5

x_{1, 2} = \frac{- ( - 13 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 13 ) - 5}{2 \cdot 1}

x = \frac{- ( - 13 ) + 5}{2 \cdot 1} : 9

x = \frac{- ( - 13 ) - 5}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

x = 9, x = 4

2 x = \frac{5}{4}

\frac{11}{36}

\frac{z ^{9}}{z ^{3}}

w^{2} + 14 w - 15 = 0

x^{4} - x^{3} + x - 1

What are the solutions to the equation x=(x-6)^2 ?
The solutions to the equation x=(x-6)^2 are x=9,x=4
Find the zeros of x=(x-6)^2
The zeros of x=(x-6)^2 are x=9,x=4