What are the solutions to the equation x^2-x+0.5=0 ?

The solutions to the equation x^2-x+0.5=0 are x= 1/2+i 1/2 ,x= 1/2-i 1/2

Find the zeros of x^2-x+0.5=0

The zeros of x^2-x+0.5=0 are x= 1/2+i 1/2 ,x= 1/2-i 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - x + 0.5 = 0

x = \frac{1}{2} + i \frac{1}{2}, x = \frac{1}{2} - i \frac{1}{2}

Solution steps

x^{2} - x + 0.5 = 0

Multiply both sides by

10

10 x^{2} - 10 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 10 \cdot 5}{2 \cdot 10}

Simplify

(- 10)^{2} - 4 \cdot 10 \cdot 5 : 10 i

x_{1, 2} = \frac{- ( - 10 ) \pm 10 i}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 10 i}{2 \cdot 10}, x_{2} = \frac{- ( - 10 ) - 10 i}{2 \cdot 10}

x = \frac{- ( - 10 ) + 10 i}{2 \cdot 10} : \frac{1}{2} + i \frac{1}{2}

x = \frac{- ( - 10 ) - 10 i}{2 \cdot 10} : \frac{1}{2} - i \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{1}{2}, x = \frac{1}{2} - i \frac{1}{2}

\frac{x - 3}{x - 5} > 0

9 x^{2} + 6 x + 5 = 0

y^{- \frac{3}{2}}

4 x^{2} + 17 x + 18

6 t^{2} + 7 t - 5

What are the solutions to the equation x^2-x+0.5=0 ?
The solutions to the equation x^2-x+0.5=0 are x= 1/2+i 1/2 ,x= 1/2-i 1/2
Find the zeros of x^2-x+0.5=0
The zeros of x^2-x+0.5=0 are x= 1/2+i 1/2 ,x= 1/2-i 1/2