What are the solutions to the equation 9x^2+6x+5=0 ?

The solutions to the equation 9x^2+6x+5=0 are x=-1/3+i 2/3 ,x=-1/3-i 2/3

Find the zeros of 9x^2+6x+5=0

The zeros of 9x^2+6x+5=0 are x=-1/3+i 2/3 ,x=-1/3-i 2/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9 x^{2} + 6 x + 5 = 0

x = - \frac{1}{3} + i \frac{2}{3}, x = - \frac{1}{3} - i \frac{2}{3}

Solution steps

9 x^{2} + 6 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 \cdot 5}{2 \cdot 9}

Simplify

6^{2} - 4 \cdot 9 \cdot 5 : 12 i

x_{1, 2} = \frac{- 6 \pm 12 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 6 + 12 i}{2 \cdot 9}, x_{2} = \frac{- 6 - 12 i}{2 \cdot 9}

x = \frac{- 6 + 12 i}{2 \cdot 9} : - \frac{1}{3} + i \frac{2}{3}

x = \frac{- 6 - 12 i}{2 \cdot 9} : - \frac{1}{3} - i \frac{2}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{3} + i \frac{2}{3}, x = - \frac{1}{3} - i \frac{2}{3}

y^{- \frac{3}{2}}

4 x^{2} + 17 x + 18

6 t^{2} + 7 t - 5

o = (\frac{69 - 3 + 0}{3}) + 1

5 x^{2} = - 4

What are the solutions to the equation 9x^2+6x+5=0 ?
The solutions to the equation 9x^2+6x+5=0 are x=-1/3+i 2/3 ,x=-1/3-i 2/3
Find the zeros of 9x^2+6x+5=0
The zeros of 9x^2+6x+5=0 are x=-1/3+i 2/3 ,x=-1/3-i 2/3