What are the solutions to the equation 4x^2-16x-26=-21 ?

The solutions to the equation 4x^2-16x-26=-21 are x=(4+sqrt(21))/2 ,x=(4-sqrt(21))/2

Find the zeros of 4x^2-16x-26=-21

The zeros of 4x^2-16x-26=-21 are x=(4+sqrt(21))/2 ,x=(4-sqrt(21))/2

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4 x^{2} - 16 x - 26 = - 21

x = \frac{4 + 21}{2}, x = \frac{4 - 21}{2}

Decimal Notation

x = 4.29128 \dots, x = - 0.29128 \dots

Solution steps

4 x^{2} - 16 x - 26 = - 21

Move

21

to the left side

4 x^{2} - 16 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 4 ( - 5 )}{2 \cdot 4}

(- 16)^{2} - 4 \cdot 4 (- 5) = 421

x_{1, 2} = \frac{- ( - 16 ) \pm 4 21}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4 21}{2 \cdot 4}, x_{2} = \frac{- ( - 16 ) - 4 21}{2 \cdot 4}

x = \frac{- ( - 16 ) + 4 21}{2 \cdot 4} : \frac{4 + 21}{2}

x = \frac{- ( - 16 ) - 4 21}{2 \cdot 4} : \frac{4 - 21}{2}

The solutions to the quadratic equation are:

x = \frac{4 + 21}{2}, x = \frac{4 - 21}{2}

ln (1) - ln (2)

- 4 x - 23 = - 6

- 4 x^{2} - 8 x - 3 = - 3 - 5 x^{2}

\frac{4 k}{k - 6} + \frac{k}{6 - k}

2 \times 1 + 2 \times \frac{24}{4}

What are the solutions to the equation 4x^2-16x-26=-21 ?
The solutions to the equation 4x^2-16x-26=-21 are x=(4+sqrt(21))/2 ,x=(4-sqrt(21))/2
Find the zeros of 4x^2-16x-26=-21
The zeros of 4x^2-16x-26=-21 are x=(4+sqrt(21))/2 ,x=(4-sqrt(21))/2