What are the solutions to the equation (a-9)(2a+1)=0 ?

The solutions to the equation (a-9)(2a+1)=0 are a=9,a=-1/2

Find the zeros of (a-9)(2a+1)=0

The zeros of (a-9)(2a+1)=0 are a=9,a=-1/2

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(a - 9) (2 a + 1) = 0

a = 9, a = - \frac{1}{2}

Decimal Notation

a = 9, a = - 0.5

Solution steps

(a - 9) (2 a + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

a - 9 = 0 or 2 a + 1 = 0

Solve

a - 9 = 0 : a = 9

Solve

2 a + 1 = 0 : a = - \frac{1}{2}

The solutions to the quadratic equation are:

a = 9, a = - \frac{1}{2}

6 x^{2} - 8 = x

5 x - 8 \geq - 8 x + 18

x^{2} < 3 x

12 y^{2} + 21 y^{5}

x^{2} - 3 x + 27 = 6 x + 7

What are the solutions to the equation (a-9)(2a+1)=0 ?
The solutions to the equation (a-9)(2a+1)=0 are a=9,a=-1/2
Find the zeros of (a-9)(2a+1)=0
The zeros of (a-9)(2a+1)=0 are a=9,a=-1/2