What is the answer to 4(3w-5)+2(w+5)-(3w-11)=67 ?

The answer to 4(3w-5)+2(w+5)-(3w-11)=67 is w=6

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4(3w-5)+2(w+5)-(3w-11)=67

4 (3 w - 5) + 2 (w + 5) - (3 w - 11) = 67

w = 6

Solution steps

4 (3 w - 5) + 2 (w + 5) - (3 w - 11) = 67

Expand

4 (3 w - 5) + 2 (w + 5) - (3 w - 11) : 11 w + 1

11 w + 1 = 67

Move

1

to the right side

11 w = 66

Divide both sides by

11

w = 6

A^{2} (\frac{π}{\frac{1}{2}}) = 1

81 = a^{2}

2 x^{2} + 8 = 4

2 x^{2} - x - 3 = 0

\frac{4}{5} - 2

What is the answer to 4(3w-5)+2(w+5)-(3w-11)=67 ?
The answer to 4(3w-5)+2(w+5)-(3w-11)=67 is w=6
Solve for w: 4(3w-5)+2(w+5)-(3w-11)=67
The solution is w=6