What are the solutions to the equation 6x^2-5x+2=0 ?

The solutions to the equation 6x^2-5x+2=0 are x= 5/12+i(sqrt(23))/(12),x= 5/12-i(sqrt(23))/(12)

Find the zeros of 6x^2-5x+2=0

The zeros of 6x^2-5x+2=0 are x= 5/12+i(sqrt(23))/(12),x= 5/12-i(sqrt(23))/(12)

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6 x^{2} - 5 x + 2 = 0

x = \frac{5}{12} + i \frac{23}{12}, x = \frac{5}{12} - i \frac{23}{12}

Solution steps

6 x^{2} - 5 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 6 \cdot 2}{2 \cdot 6}

Simplify

(- 5)^{2} - 4 \cdot 6 \cdot 2 : 23 i

x_{1, 2} = \frac{- ( - 5 ) \pm 23 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 23 i}{2 \cdot 6}, x_{2} = \frac{- ( - 5 ) - 23 i}{2 \cdot 6}

x = \frac{- ( - 5 ) + 23 i}{2 \cdot 6} : \frac{5}{12} + i \frac{23}{12}

x = \frac{- ( - 5 ) - 23 i}{2 \cdot 6} : \frac{5}{12} - i \frac{23}{12}

The solutions to the quadratic equation are:

x = \frac{5}{12} + i \frac{23}{12}, x = \frac{5}{12} - i \frac{23}{12}

lo g_{x} (a) + 3 lo g_{x} (b) + 2 lo g_{x} (c)

4 (\frac{1}{4})^{1 + 2}

4.5 = 0.5 n

x^{2} - x + 1 = 43

5 + 25

What are the solutions to the equation 6x^2-5x+2=0 ?
The solutions to the equation 6x^2-5x+2=0 are x= 5/12+i(sqrt(23))/(12),x= 5/12-i(sqrt(23))/(12)
Find the zeros of 6x^2-5x+2=0
The zeros of 6x^2-5x+2=0 are x= 5/12+i(sqrt(23))/(12),x= 5/12-i(sqrt(23))/(12)