What are the solutions to the equation 4x^2+400=0 ?

The solutions to the equation 4x^2+400=0 are x=10i,x=-10i

Find the zeros of 4x^2+400=0

The zeros of 4x^2+400=0 are x=10i,x=-10i

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4 x^{2} + 400 = 0

x = 10 i, x = - 10 i

Solution steps

4 x^{2} + 400 = 0

Move

400

to the right side

4 x^{2} = - 400

Divide both sides by

4

x^{2} = - 100

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 100, x = - - 100

- 100 = 10 i

- - 100 = - 10 i

x = 10 i, x = - 10 i

4 b^{2} - 4 b + 7 = 6

3 a^{2} + a^{3} b^{2} - 5 a^{2} b

\frac{6 ^{6}}{6 ^{3}}

\frac{Q}{12} = 32

5 x^{2} + 10 x - 75

What are the solutions to the equation 4x^2+400=0 ?
The solutions to the equation 4x^2+400=0 are x=10i,x=-10i
Find the zeros of 4x^2+400=0
The zeros of 4x^2+400=0 are x=10i,x=-10i