What are the solutions to the equation 4=16t^2 ?

The solutions to the equation 4=16t^2 are t= 1/2 ,t=-1/2

Find the zeros of 4=16t^2

The zeros of 4=16t^2 are t= 1/2 ,t=-1/2

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4 = 16 t^{2}

t = \frac{1}{2}, t = - \frac{1}{2}

Decimal Notation

t = 0.5, t = - 0.5

Solution steps

4 = 16 t^{2}

Switch sides

16 t^{2} = 4

Divide both sides by

16

t^{2} = \frac{1}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = \frac{1}{4}, t = - \frac{1}{4}

\frac{1}{4} = \frac{1}{2}

- \frac{1}{4} = - \frac{1}{2}

t = \frac{1}{2}, t = - \frac{1}{2}

4 (3 x + 2) = 4 (2 x + 3) + 4 x

25 x^{2} - 169

\frac{4 x y}{4 x}

\frac{( 2 - x ) ( 2 x + 1 ) ^{2}}{( x - 4 ) ^{4}} \leq 0

3 u^{2} + 10 u + 7

What are the solutions to the equation 4=16t^2 ?
The solutions to the equation 4=16t^2 are t= 1/2 ,t=-1/2
Find the zeros of 4=16t^2
The zeros of 4=16t^2 are t= 1/2 ,t=-1/2