What are the solutions to the equation 1^2+x^2=2^2 ?

The solutions to the equation 1^2+x^2=2^2 are x=sqrt(3),x=-sqrt(3)

Find the zeros of 1^2+x^2=2^2

The zeros of 1^2+x^2=2^2 are x=sqrt(3),x=-sqrt(3)

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1^{2} + x^{2} = 2^{2}

x = 3, x = - 3

Decimal Notation

x = 1.73205 \dots, x = - 1.73205 \dots

Solution steps

1^{2} + x^{2} = 2^{2}

Move

1^{2}

to the right side

x^{2} = 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 3, x = - 3

x^{2} + 18 x = - 80

x^{2} = 12 x - 20

\frac{3 x ^{3} y ^{- 1} z ^{- 1}}{x ^{- 4} y ^{0} z ^{0}}

\frac{1}{- \frac{24}{25}}

x^{- \frac{1}{2}} \cdot x^{- \frac{1}{2}}

What are the solutions to the equation 1^2+x^2=2^2 ?
The solutions to the equation 1^2+x^2=2^2 are x=sqrt(3),x=-sqrt(3)
Find the zeros of 1^2+x^2=2^2
The zeros of 1^2+x^2=2^2 are x=sqrt(3),x=-sqrt(3)