What are the solutions to the equation x^2+18x=-80 ?

The solutions to the equation x^2+18x=-80 are x=-8,x=-10

Find the zeros of x^2+18x=-80

The zeros of x^2+18x=-80 are x=-8,x=-10

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x^{2} + 18 x = - 80

x = - 8, x = - 10

Solution steps

x^{2} + 18 x = - 80

Move

80

to the left side

x^{2} + 18 x + 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 80}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot 80 = 2

x_{1, 2} = \frac{- 18 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 2}{2 \cdot 1}, x_{2} = \frac{- 18 - 2}{2 \cdot 1}

x = \frac{- 18 + 2}{2 \cdot 1} : - 8

x = \frac{- 18 - 2}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = - 8, x = - 10

x^{2} = 12 x - 20

\frac{3 x ^{3} y ^{- 1} z ^{- 1}}{x ^{- 4} y ^{0} z ^{0}}

\frac{1}{- \frac{24}{25}}

x^{- \frac{1}{2}} \cdot x^{- \frac{1}{2}}

(z + 3)^{2} = 5

What are the solutions to the equation x^2+18x=-80 ?
The solutions to the equation x^2+18x=-80 are x=-8,x=-10
Find the zeros of x^2+18x=-80
The zeros of x^2+18x=-80 are x=-8,x=-10