What are the solutions to the equation 4(6-3x)^2+42=43 ?

The solutions to the equation 4(6-3x)^2+42=43 are x= 11/6 ,x= 13/6

Find the zeros of 4(6-3x)^2+42=43

The zeros of 4(6-3x)^2+42=43 are x= 11/6 ,x= 13/6

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4 (6 - 3 x)^{2} + 42 = 43

x = \frac{11}{6}, x = \frac{13}{6}

Solution steps

4 (6 - 3 x)^{2} + 42 = 43

Move

42

to the right side

4 (6 - 3 x)^{2} = 1

Divide both sides by

4

(6 - 3 x)^{2} = \frac{1}{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

6 - 3 x = \frac{1}{4} : x = \frac{11}{6}

Solve

6 - 3 x = - \frac{1}{4} : x = \frac{13}{6}

The solutions to the quadratic equation are:

x = \frac{11}{6}, x = \frac{13}{6}

2 c^{2} + c = 6

- \frac{1}{2} x = 4

5 (- 2 k - 3) + 2 k

- ∣ 6 c ∣ - 2 > - 10

1^{- \frac{2}{3}}

What are the solutions to the equation 4(6-3x)^2+42=43 ?
The solutions to the equation 4(6-3x)^2+42=43 are x= 11/6 ,x= 13/6
Find the zeros of 4(6-3x)^2+42=43
The zeros of 4(6-3x)^2+42=43 are x= 11/6 ,x= 13/6