What are the solutions to the equation a^2-9a+8=0 ?

The solutions to the equation a^2-9a+8=0 are a=8,a=1

Find the zeros of a^2-9a+8=0

The zeros of a^2-9a+8=0 are a=8,a=1

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a^{2} - 9 a + 8 = 0

a = 8, a = 1

Solution steps

a^{2} - 9 a + 8 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 8 = 7

a_{1, 2} = \frac{- ( - 9 ) \pm 7}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 9 ) + 7}{2 \cdot 1}, a_{2} = \frac{- ( - 9 ) - 7}{2 \cdot 1}

a = \frac{- ( - 9 ) + 7}{2 \cdot 1} : 8

a = \frac{- ( - 9 ) - 7}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

a = 8, a = 1

2 ∣ x + 5 ∣ = 4

\frac{8}{5}

- 10 - 8 v = - 2 v^{2}

2 m (8 - m) + 9 n (8 - m)

2115 + 75

What are the solutions to the equation a^2-9a+8=0 ?
The solutions to the equation a^2-9a+8=0 are a=8,a=1
Find the zeros of a^2-9a+8=0
The zeros of a^2-9a+8=0 are a=8,a=1