What are the solutions to the equation -10-8v=-2v^2 ?

The solutions to the equation -10-8v=-2v^2 are v=-1,v=5

Find the zeros of -10-8v=-2v^2

The zeros of -10-8v=-2v^2 are v=-1,v=5

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- 10 - 8 v = - 2 v^{2}

v = - 1, v = 5

Solution steps

- 10 - 8 v = - 2 v^{2}

Switch sides

- 2 v^{2} = - 10 - 8 v

Move

8 v

to the left side

- 2 v^{2} + 8 v = - 10

Move

10

to the left side

- 2 v^{2} + 8 v + 10 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 2 ) \cdot 10}{2 ( - 2 )}

8^{2} - 4 (- 2) \cdot 10 = 12

v_{1, 2} = \frac{- 8 \pm 12}{2 ( - 2 )}

Separate the solutions

v_{1} = \frac{- 8 + 12}{2 ( - 2 )}, v_{2} = \frac{- 8 - 12}{2 ( - 2 )}

v = \frac{- 8 + 12}{2 ( - 2 )} : - 1

v = \frac{- 8 - 12}{2 ( - 2 )} : 5

The solutions to the quadratic equation are:

v = - 1, v = 5

2 m (8 - m) + 9 n (8 - m)

2115 + 75

(\frac{3 a ^{- 2}}{4 b ^{- \frac{1}{3}}})^{- 1}

272

p^{4} + 3 p^{3} - 8 p - 24

What are the solutions to the equation -10-8v=-2v^2 ?
The solutions to the equation -10-8v=-2v^2 are v=-1,v=5
Find the zeros of -10-8v=-2v^2
The zeros of -10-8v=-2v^2 are v=-1,v=5