What are the solutions to the equation (x^2+4)=0 ?

The solutions to the equation (x^2+4)=0 are x=2i,x=-2i

Find the zeros of (x^2+4)=0

The zeros of (x^2+4)=0 are x=2i,x=-2i

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(x^{2} + 4) = 0

x = 2 i, x = - 2 i

Solution steps

(x^{2} + 4) = 0

x^{2} + 4 = 0

Move

4

to the right side

x^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 4, x = - - 4

- 4 = 2 i

- - 4 = - 2 i

x = 2 i, x = - 2 i

1 + \frac{5 x}{7} - \frac{1}{5} (x + 7) \geq x

25 x - 17 x = - 64

1792

5 x - 9 = 11 x + 15

(5 y + 2) (y - 3) = - 13 (2 + y)

What are the solutions to the equation (x^2+4)=0 ?
The solutions to the equation (x^2+4)=0 are x=2i,x=-2i
Find the zeros of (x^2+4)=0
The zeros of (x^2+4)=0 are x=2i,x=-2i