What are the solutions to the equation 14-x^2=-5x-10 ?

The solutions to the equation 14-x^2=-5x-10 are x=-3,x=8

Find the zeros of 14-x^2=-5x-10

The zeros of 14-x^2=-5x-10 are x=-3,x=8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

14 - x^{2} = - 5 x - 10

x = - 3, x = 8

Solution steps

14 - x^{2} = - 5 x - 10

Move

10

to the left side

- x^{2} + 24 = - 5 x

Move

5 x

to the left side

- x^{2} + 24 + 5 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 5 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 1 ) \cdot 24}{2 ( - 1 )}

5^{2} - 4 (- 1) \cdot 24 = 11

x_{1, 2} = \frac{- 5 \pm 11}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 5 + 11}{2 ( - 1 )}, x_{2} = \frac{- 5 - 11}{2 ( - 1 )}

x = \frac{- 5 + 11}{2 ( - 1 )} : - 3

x = \frac{- 5 - 11}{2 ( - 1 )} : 8

The solutions to the quadratic equation are:

x = - 3, x = 8

(6 a b^{3} c^{4}) (- 3 a^{2} b^{3} c)

- 39 x = 702

1 + 4 x + 6 x^{2} + 4 x^{3} + x^{4}

\frac{4}{5} n + 2 = \frac{2}{5} n - 4

\frac{3 x + 3}{4 x - 1} - \frac{9}{2 x - 3} \leq 0

What are the solutions to the equation 14-x^2=-5x-10 ?
The solutions to the equation 14-x^2=-5x-10 are x=-3,x=8
Find the zeros of 14-x^2=-5x-10
The zeros of 14-x^2=-5x-10 are x=-3,x=8