What is |x+2|-|x-1|>2 ?

The solution to |x+2|-|x-1|>2 is x> 1/2

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|x+2|-|x-1|>2

∣ x + 2 ∣ - ∣ x - 1 ∣ > 2

x > \frac{1}{2}

Interval Notation

(\frac{1}{2}, \infty)

Decimal Notation

x > 0.5

Solution steps

∣ x + 2 ∣ - ∣ x - 1 ∣ > 2

Find positive and negative intervals

x < - 2, - 2 \leq x < 1, x \geq 1

Solve the inequality for each interval

No Solution or \frac{1}{2} < x < 1 or x \geq 1

Merge Overlapping Intervals

x > \frac{1}{2}

lo g_{3} (\frac{1}{3})

\frac{1}{X + 1} > \frac{1}{1 - X}

p^{2} + 2 p - 63 = 0

9 x^{2} - 27 x + 20 = 0

5 \cdot 1 0^{- 6}