What are the solutions to the equation m^2-6m+3m=2 ?

The solutions to the equation m^2-6m+3m=2 are m=(3+sqrt(17))/2 ,m=(3-sqrt(17))/2

Find the zeros of m^2-6m+3m=2

The zeros of m^2-6m+3m=2 are m=(3+sqrt(17))/2 ,m=(3-sqrt(17))/2

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m^{2} - 6 m + 3 m = 2

m = \frac{3 + 17}{2}, m = \frac{3 - 17}{2}

Decimal Notation

m = 3.56155 \dots, m = - 0.56155 \dots

Solution steps

m^{2} - 6 m + 3 m = 2

Refine

m^{2} - 3 m = 2

Move

2

to the left side

m^{2} - 3 m - 2 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 2) = 17

m_{1, 2} = \frac{- ( - 3 ) \pm 17}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 3 ) + 17}{2 \cdot 1}, m_{2} = \frac{- ( - 3 ) - 17}{2 \cdot 1}

m = \frac{- ( - 3 ) + 17}{2 \cdot 1} : \frac{3 + 17}{2}

m = \frac{- ( - 3 ) - 17}{2 \cdot 1} : \frac{3 - 17}{2}

The solutions to the quadratic equation are:

m = \frac{3 + 17}{2}, m = \frac{3 - 17}{2}

36000 + \frac{8}{21}

(x^{2} + 2 x + 4) = 0

- x > 3

3 c + 7 c + \frac{c}{4 c}

ln (12) - ln (6)

What are the solutions to the equation m^2-6m+3m=2 ?
The solutions to the equation m^2-6m+3m=2 are m=(3+sqrt(17))/2 ,m=(3-sqrt(17))/2
Find the zeros of m^2-6m+3m=2
The zeros of m^2-6m+3m=2 are m=(3+sqrt(17))/2 ,m=(3-sqrt(17))/2