What are the solutions to the equation 25p^2-16=0 ?

The solutions to the equation 25p^2-16=0 are p= 4/5 ,p=-4/5

Find the zeros of 25p^2-16=0

The zeros of 25p^2-16=0 are p= 4/5 ,p=-4/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

25 p^{2} - 16 = 0

p = \frac{4}{5}, p = - \frac{4}{5}

Decimal Notation

p = 0.8, p = - 0.8

Solution steps

25 p^{2} - 16 = 0

Move

16

to the right side

25 p^{2} = 16

Divide both sides by

25

p^{2} = \frac{16}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

p = \frac{16}{25}, p = - \frac{16}{25}

\frac{16}{25} = \frac{4}{5}

- \frac{16}{25} = - \frac{4}{5}

p = \frac{4}{5}, p = - \frac{4}{5}

r^{2} + 4 r + 5 = 0

4 x^{2} + 12 x = 8 x - 4

x (x + 4) = 117

5 - 8 v < 11 - 6 v

4 x^{2} - 12 x - 27 = 0

What are the solutions to the equation 25p^2-16=0 ?
The solutions to the equation 25p^2-16=0 are p= 4/5 ,p=-4/5
Find the zeros of 25p^2-16=0
The zeros of 25p^2-16=0 are p= 4/5 ,p=-4/5