What is factor m^2-4m+3 ?

The solution to factor m^2-4m+3 is (m-1)(m-3)

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factor m^2-4m+3

factor

m^{2} - 4 m + 3

(m - 1) (m - 3)

Solution steps

m^{2} - 4 m + 3

Break the expression into groups

= (m^{2} - m) + (- 3 m + 3)

Factor out

m

from

m^{2} - m : m (m - 1)

Factor out

- 3

from

- 3 m + 3 : - 3 (m - 1)

= m (m - 1) - 3 (m - 1)

Factor out common term

m - 1

= (m - 1) (m - 3)

x^{4} - 17 x^{2} + 72

\frac{x + 1}{x - 1} \leq 0

63 n^{2} + 62 n + 15

- 12 x^{2} + 6 x = 0

x^{2} + 8 x + 1 \geq - 14