What are the solutions to the equation -12x^2+6x=0 ?

The solutions to the equation -12x^2+6x=0 are x=0,x= 1/2

Find the zeros of -12x^2+6x=0

The zeros of -12x^2+6x=0 are x=0,x= 1/2

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- 12 x^{2} + 6 x = 0

x = 0, x = \frac{1}{2}

Decimal Notation

x = 0, x = 0.5

Solution steps

- 12 x^{2} + 6 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 12 ) \cdot 0}{2 ( - 12 )}

6^{2} - 4 (- 12) \cdot 0 = 6

x_{1, 2} = \frac{- 6 \pm 6}{2 ( - 12 )}

Separate the solutions

x_{1} = \frac{- 6 + 6}{2 ( - 12 )}, x_{2} = \frac{- 6 - 6}{2 ( - 12 )}

x = \frac{- 6 + 6}{2 ( - 12 )} : 0

x = \frac{- 6 - 6}{2 ( - 12 )} : \frac{1}{2}

The solutions to the quadratic equation are:

x = 0, x = \frac{1}{2}

x^{2} + 8 x + 1 \geq - 14

1. 2^{2}

x^{2} - 3 x + 10 = 0

- 1 \cdot 2

\frac{1}{8} - \frac{3}{4}

What are the solutions to the equation -12x^2+6x=0 ?
The solutions to the equation -12x^2+6x=0 are x=0,x= 1/2
Find the zeros of -12x^2+6x=0
The zeros of -12x^2+6x=0 are x=0,x= 1/2