What are the solutions to the equation v^2-6v=-91 ?

The solutions to the equation v^2-6v=-91 are v=3+sqrt(82)i,v=3-sqrt(82)i

Find the zeros of v^2-6v=-91

The zeros of v^2-6v=-91 are v=3+sqrt(82)i,v=3-sqrt(82)i

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v^{2} - 6 v = - 91

v = 3 + 82 i, v = 3 - 82 i

Solution steps

v^{2} - 6 v = - 91

Move

91

to the left side

v^{2} - 6 v + 91 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 91}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 91 : 282 i

v_{1, 2} = \frac{- ( - 6 ) \pm 2 82 i}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- ( - 6 ) + 2 82 i}{2 \cdot 1}, v_{2} = \frac{- ( - 6 ) - 2 82 i}{2 \cdot 1}

v = \frac{- ( - 6 ) + 2 82 i}{2 \cdot 1} : 3 + 82 i

v = \frac{- ( - 6 ) - 2 82 i}{2 \cdot 1} : 3 - 82 i

The solutions to the quadratic equation are:

v = 3 + 82 i, v = 3 - 82 i

\frac{6 x + 1}{12} = \frac{x}{6}

23 + 18 y = - 21 + 14 y

x^{2} - 7 x \geq 18

\frac{3 - 2 x}{( x + 2 ) ( 7 - x )} \leq 0

(\frac{1}{16})^{- \frac{5}{4}}

What are the solutions to the equation v^2-6v=-91 ?
The solutions to the equation v^2-6v=-91 are v=3+sqrt(82)i,v=3-sqrt(82)i
Find the zeros of v^2-6v=-91
The zeros of v^2-6v=-91 are v=3+sqrt(82)i,v=3-sqrt(82)i