What are the solutions to the equation 2x^2+3x-35=0 ?

The solutions to the equation 2x^2+3x-35=0 are x= 7/2 ,x=-5

Find the zeros of 2x^2+3x-35=0

The zeros of 2x^2+3x-35=0 are x= 7/2 ,x=-5

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2 x^{2} + 3 x - 35 = 0

x = \frac{7}{2}, x = - 5

Decimal Notation

x = 3.5, x = - 5

Solution steps

2 x^{2} + 3 x - 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 ( - 35 )}{2 \cdot 2}

3^{2} - 4 \cdot 2 (- 35) = 17

x_{1, 2} = \frac{- 3 \pm 17}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 17}{2 \cdot 2}, x_{2} = \frac{- 3 - 17}{2 \cdot 2}

x = \frac{- 3 + 17}{2 \cdot 2} : \frac{7}{2}

x = \frac{- 3 - 17}{2 \cdot 2} : - 5

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = - 5

9^{2} + b^{2} = 1 1^{2}

x^{5} - x

x - 5 \cdot x + 2

(64 n^{9})^{\frac{2}{3}}

12 + 2 x - x = 9 x + 6

What are the solutions to the equation 2x^2+3x-35=0 ?
The solutions to the equation 2x^2+3x-35=0 are x= 7/2 ,x=-5
Find the zeros of 2x^2+3x-35=0
The zeros of 2x^2+3x-35=0 are x= 7/2 ,x=-5