What are the solutions to the equation 6x^2-7x=2 ?

The solutions to the equation 6x^2-7x=2 are x=(7+sqrt(97))/(12),x=(7-sqrt(97))/(12)

Find the zeros of 6x^2-7x=2

The zeros of 6x^2-7x=2 are x=(7+sqrt(97))/(12),x=(7-sqrt(97))/(12)

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6 x^{2} - 7 x = 2

x = \frac{7 + 97}{12}, x = \frac{7 - 97}{12}

Decimal Notation

x = 1.40407 \dots, x = - 0.23740 \dots

Solution steps

6 x^{2} - 7 x = 2

Move

2

to the left side

6 x^{2} - 7 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 6 ( - 2 )}{2 \cdot 6}

(- 7)^{2} - 4 \cdot 6 (- 2) = 97

x_{1, 2} = \frac{- ( - 7 ) \pm 97}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 97}{2 \cdot 6}, x_{2} = \frac{- ( - 7 ) - 97}{2 \cdot 6}

x = \frac{- ( - 7 ) + 97}{2 \cdot 6} : \frac{7 + 97}{12}

x = \frac{- ( - 7 ) - 97}{2 \cdot 6} : \frac{7 - 97}{12}

The solutions to the quadratic equation are:

x = \frac{7 + 97}{12}, x = \frac{7 - 97}{12}

\frac{11 !}{2 ! ( 11 - 2 ) !}

3 x - 4 \geq 5

8 \cdot 5

\frac{( 4 p ^{- 4} q ) ^{- 2}}{10 p q ^{- 3}}

7 x - 8 < 4 x + 7

What are the solutions to the equation 6x^2-7x=2 ?
The solutions to the equation 6x^2-7x=2 are x=(7+sqrt(97))/(12),x=(7-sqrt(97))/(12)
Find the zeros of 6x^2-7x=2
The zeros of 6x^2-7x=2 are x=(7+sqrt(97))/(12),x=(7-sqrt(97))/(12)