What are the solutions to the equation 3x^2+24x-27=0 ?

The solutions to the equation 3x^2+24x-27=0 are x=1,x=-9

Find the zeros of 3x^2+24x-27=0

The zeros of 3x^2+24x-27=0 are x=1,x=-9

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3 x^{2} + 24 x - 27 = 0

x = 1, x = - 9

Solution steps

3 x^{2} + 24 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 3 ( - 27 )}{2 \cdot 3}

2 4^{2} - 4 \cdot 3 (- 27) = 30

x_{1, 2} = \frac{- 24 \pm 30}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 24 + 30}{2 \cdot 3}, x_{2} = \frac{- 24 - 30}{2 \cdot 3}

x = \frac{- 24 + 30}{2 \cdot 3} : 1

x = \frac{- 24 - 30}{2 \cdot 3} : - 9

The solutions to the quadratic equation are:

x = 1, x = - 9

- 8 x^{2} + 7 = 4

15 x + 15 < 3 (5 x + 20)

\frac{4}{3} \cdot 27

3^{- 0.5}

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What are the solutions to the equation 3x^2+24x-27=0 ?
The solutions to the equation 3x^2+24x-27=0 are x=1,x=-9
Find the zeros of 3x^2+24x-27=0
The zeros of 3x^2+24x-27=0 are x=1,x=-9