What are the solutions to the equation x^2+5=-5x ?

The solutions to the equation x^2+5=-5x are x=(-5+sqrt(5))/2 ,x=(-5-sqrt(5))/2

Find the zeros of x^2+5=-5x

The zeros of x^2+5=-5x are x=(-5+sqrt(5))/2 ,x=(-5-sqrt(5))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 5 = - 5 x

x = \frac{- 5 + 5}{2}, x = \frac{- 5 - 5}{2}

Decimal Notation

x = - 1.38196 \dots, x = - 3.61803 \dots

Solution steps

x^{2} + 5 = - 5 x

Move

5 x

to the left side

x^{2} + 5 + 5 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 5 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 5 = 5

x_{1, 2} = \frac{- 5 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 5}{2 \cdot 1}, x_{2} = \frac{- 5 - 5}{2 \cdot 1}

x = \frac{- 5 + 5}{2 \cdot 1} : \frac{- 5 + 5}{2}

x = \frac{- 5 - 5}{2 \cdot 1} : \frac{- 5 - 5}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 5}{2}, x = \frac{- 5 - 5}{2}

2 (x^{3} - 1) - 3 (x^{2} - 1)

\frac{x - 6}{x - 1} \geq 0

t - 8 = 14

f = 3 (5) + 2

\frac{x + 1}{3} = - 2

What are the solutions to the equation x^2+5=-5x ?
The solutions to the equation x^2+5=-5x are x=(-5+sqrt(5))/2 ,x=(-5-sqrt(5))/2
Find the zeros of x^2+5=-5x
The zeros of x^2+5=-5x are x=(-5+sqrt(5))/2 ,x=(-5-sqrt(5))/2